On electrolysis of dil. sulphuric acid using Platinum (Pt) electrode, the product obtained at anode will be :

$\begin{array}{l}{\mathrm{H}}_2{\mathrm{SO}}_4⟶2{\mathrm{H}}^{+}+{\mathrm{SO}}_4^{2-}\\ (\mathrm{dilute}) \\ \mathrm{Sulphate} \mathrm{ion} \mathrm{can} \mathrm{never} \mathrm{oxidise}, \mathrm{sulphur} \mathrm{in} \mathrm{highest} \mathrm{ox}.\mathrm{state}; \\ \mathrm{At} \mathrm{anode}, 2{\mathrm{H}}_2\mathrm{O}⟶4{\mathrm{H}}^{+}+4{\mathrm{e}}^{-}+{\mathrm{O}}_2\end{array}$