On electrolysis, of dilute sulfuric acid using platinum electrodes, the major product obtained at the anode will be

Dissociation of sulfuric acid gives hydrogen ions and sulfate ions.

${\mathrm{H}}_2{\mathrm{SO}}_4\to 2{\mathrm{H}}^{+}+{\mathrm{SO}}_4^{2-}$

Dissociation of water gives hydrogen ion and hydroxide ion.

${\mathrm{H}}_2\mathrm{O}\rightleftharpoons {\mathrm{H}}^{+}+{\mathrm{OH}}^{-}$

When sulfuric acid undergoes electrolysis, then oxygen and sulfur dioxide form at the anode but oxygen gas is produced in large quantity because the reduction potential of the hydroxide ion is greater than the sulfate ion.

$\begin{array}{cccc}\mathrm{Anode}:& 4{\mathrm{OH}}^{-}& \to & 2{\mathrm{H}}_2\mathrm{O}+{\mathrm{O}}_2+4{\mathrm{e}}^{-}\\ & {\mathrm{SO}}_4^{2-}+{\mathrm{H}}^{+}& \to & 2{\mathrm{H}}_2\mathrm{O}+{\mathrm{SO}}_2+4{\mathrm{e}}^{-}\end{array}$

At the cathode, hydrogen gas is formed.

$\mathrm{Cathode}: 2{\mathrm{H}}^{+}+2{\mathrm{e}}^{-}\to 2{\mathrm{H}}_2$