On hydrolysis of a "compound", two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollen's reagent and Fehling's solution. The "compound" is

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${CH}_{3} {CH}_{2} {CH}_{2} NC$

${CH}_{3} {CH}_{2} {CH}_{2} CN$

${CH}_{3} {CH}_{2} {CH}_{2} ON = O$

${CH}_{3} {CH}_{2} {CH}_{2} CON {({CH}_{3})}_{2}$

answer is A.

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Detailed Solution

${CH}_{3} {CH}_{2} {CH}_{2} NC + 2 H_{2} O \overset{}{⟶ {CH}_{3} C H_{2} {CH}_{2} {NH}_{2} + HCOOH} I I I II (HCOOH) reduces Tollen's reagent and Fehling's solution I d o e s n o t r e s p o n d t o i o d o f o r m t e s t$

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