Q.

On increasing the length by 0.5 mm in a steel wire of length 2 m and area of cross-section  2mm2, the force required is [Y for steel =2.2×1011N/m2]]

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a

1.1×102N

b

1.1×105N

c

1.1×103N

d

1.1×104N

answer is D.

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Detailed Solution

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F=YAlL=2.2×1011×2×106×5​ ×1042=1.1×102N

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