On passing 0.5 mole of electrons through CuSO₄ and Hg₂(NO₃)₂ solutions in series using inert electrodes:

$\text{ Cathode : }{\mathrm{Cu}}_{\left(\mathrm{aq}\right)}^{2+}+2{\mathrm{e}}^{-}⟶{\mathrm{Cu}}_{\left(\mathrm{s}\right)}$
1 mole of Cu deposited $\equiv$ 2 mole of electrons
${\mathrm{Hg}}_{2\left(\mathrm{aq}\right)}^{2+}+2{\mathrm{e}}^{-}⟶2{\mathrm{Hg}}_{\left(\mathrm{l}\right)}$
1 mole of Hg, deposited $\equiv$ 1 mole of electrons
Anode (each cell) :
$2{\mathrm{H}}_2{\mathrm{O}}_{\left(1\right)}⟶4{\mathrm{H}}_{\left(\mathrm{aq}\right)}^{+}+{\mathrm{O}}_{2\left(\mathrm{g}\right)}+4{\mathrm{e}}^{-}$
1 mole of O₂ $\equiv$ 4 mole of electrons