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On passing 3 ampere of electricity for 50 minutes, 1.8 gram metal deposits. The equivalent mass of metal is:

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20.5

25.8

19.3

30.7

answer is C.

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Detailed Solution

$W_{metal} = \frac{E \times I \times t}{96500} = \frac{E \times 3 \times 50 \times 60}{96500}$

$E = \frac{96500 \times w}{3 \times 50 \times 60} = \frac{96500 \times 1 .8}{3 \times 50 \times 60} = 19 .3$

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