On passing an electric current, the quantity of deposition of a metal on cathode depends on the

On passing an electric current, the quantity of deposition of a metal on cathode depends on the quantity of current that passes through the solution. which denotes the amount of current passing through the solution.
The amount of metal that is deposited on the cathode relies on the metal ions' charge and number. 

The mass of material deposited on the cathode or anode, according to Faraday's second law of electrolyte,  $m=z\times \mathrm{l}\times \mathrm{t}$.

where, 

z = Equivalence of electrochemistry

l = existing passed

t = Time frame

$z=\frac{\left(\frac{M}{n-\text{ factor }}\right.}{F}$

M = Atomic mass
n- factor = the number of electrons acquired or lost during electrolysis

F = the constant of Faraday

$\begin{array}{l}\Rightarrow m=\frac{\left(\frac{M}{n-factor}\right.}{F}\times 1\times t\\ \Rightarrow m=\frac{MQ}{nF}(Q=1\times t)\end{array}$

Hence, correct option is D.