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On strongly heating $Pb {({NO}_{3})}_{2}$ crystals, the gas formed is

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${NO}_{2}$

$O_{2}$

${NO}_{2} + O_{2}$

answer is C.

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Detailed Solution

When solid lead nitrate is heated strongly a it turns yellow due to formation of lead oxide and a reddish brown gas is evolved which is nitrogen dioxide.

$2 Pb {({NO}_{3})}_{2} (s) \to 2 PbO (s) + 4 {NO}_{2} (g) + O_{2} (g)$

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