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Q.

On suspending a mass ‘m’ from a spring of force constant ‘K’ frequency of vibration ‘f’ is obtained. If a second spring as shown in the figure, is arranged then frequency will be

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a

f2

b

f2

c

2f

d

f

answer is A.

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Detailed Solution

f=12πKm∝K
Both springs are in parallel So, f′∝2K∝2f
f′=2f

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On suspending a mass ‘m’ from a spring of force constant ‘K’ frequency of vibration ‘f’ is obtained. If a second spring as shown in the figure, is arranged then frequency will be