On the basis of above Ellingham diagram, select the incorrect statement.

Carbon can be used to reduce any metal oxide at a high temperature.

$\mathrm{\Delta S}(\mathrm{C},\mathrm{CO})<\mathrm{\Delta S}\left(\mathrm{C},{\mathrm{CO}}_2\right)$

Upto 710^oC, formation of CO₂ is more favourable energetically but above 710^oc, the formation of CO is preferred.

Carbon reduces many oxides at elevated temperature because ${\mathrm{\Delta }}_{\mathrm{f}}{\mathrm{G}}^{\ominus }$is temperature line with negative slope.