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On the basis of Bohr's model, the approximate radius of Li++ ion in its ground state if the Bohr radius is $a_{0} = 53 p m :$

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$13 p m$

$53 p m$

$27 p m$

$18 p m$

answer is D.

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Detailed Solution

According to Bohr's model of atom, radius of an atom in its ground state.

$r = \frac{a_{0}}{Z}$ where $a_{0}$ = Bohr's radius = $53 p m$ and Z = atomic number $= 3 (f o r {L_{i}}^{+ +})$

$∴ r = \frac{53}{3} = 17.67 p m = 18 p m$

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