On the complete combustion, 2 grams of organic compound containing C,H,O gave 4.7567 g of carbon dioxide and 2.432 g of water. The empirical formula of compound is C_xH_yO_z . The value of $\frac{y \times x}{z} =$

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answer is 40.

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Detailed Solution

$\begin{array}{l} C_{4} H_{10} O \\ % C = \frac{12 \times 4 .7567 \times 100}{44 \times 2} = 64 .86 \\ % H = \frac{2 \times 2 .432 \times 100}{18 \times 2} = 13 .511 \\ % O = 21 .63 \\ x = 4, y = 10, z = 1 \end{array}$
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$\frac{x \times y}{z} = \frac{4 \times 10}{1} = 40$

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