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On treatment of 100 ml. of 0.1M solution of ${CoCl}_{3} . 6 H_{2} O$ with excess $AgNO 3, 1.2 × 1022$ ions are precipitated. The complex is :

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Co H 2 O 4 Cl 2 Cl 2 2 H 2 O

Co H 2 O 3 Cl 3 3 H 2 O

Co H 2 O 6 Cl 3

Co H 2 O 5 Cl Cl 2 H 2 O

answer is D.

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Detailed Solution

Moles of comples

= Molarity × Volume (ml) 1000 = 100 × 0.1 1000 = 0.01 mole

Moles of ions
precipitated with excess of

AgNo 3 = 1.2 × 1022 6.02 × 1023 = 0.02 moles ∴

Number of ions present in ionization sphere

= Number of moles of ions precipitated Number of molesofcomplex = 0.02 0.01 = 2 It means 2 Cl − ions

present in ionizatioin sphere.Thus formula of the complex is,

Co H 2 O 5 Cl Cl 2 H 2 O

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