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One mole of argon is expanded according to process equation $P V^{1.5} =$ constant and its temperature falls by 26 K. Then, (R=8.31 J/K mol)

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Work done by gas is 39 J

Heat exchanged is zero

Heat exchanged is 108 J

Work done by gas is 139 J

answer is A.

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Detailed Solution

$d W = \frac{n R}{γ - 1} (T_{i} - T_{f})$

$= 1 X \frac{3}{2} X 8.31 X (- 26)$

$d W = 432 J$

$d U = n c_{v} d T$ $= 1 \times \frac{3 R}{2} X 26$

$d U = - 324 J$

$d Q = d U + d W = 432 - 324 = 108 J$

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