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One car moving on a straight road covers one third of the distance with 20 km/hr and the rest with 60 km/hr. The average speed is

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40 km/hr

$46 \frac{2}{3} km / hr$

80 km/hr

36 km/hr

answer is D.

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Detailed Solution

$S_{1} = \frac{S}{3}, S_{2} = \frac{2 S}{3}$
$V_{1} = 20, V_{2} = 60 V_{Avg} = \frac{S_{1} + S_{2}}{\frac{S_{1}}{n_{1}} + \frac{S_{2}}{n_{2}}} = \frac{S}{\frac{S}{3 (20)} + \frac{2 S}{3 (60)}} = 36 kmph$

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