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Q.

One die has two faces marked 1, two faces marked 2, one face marked 3 and one face marked 4. Another die has one face marked 1, two faces marked 2, two faces marked 3 and one face marked 4. The probability of getting the sum of numbers to be 4 or 5, when both the dice are thrown together, is

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a

4/9

b

3/5

c

2/3

d

1/2

answer is A.

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Detailed Solution

a = number or dice 1
b = number on dice 2
(a,b) = (1,3), (3,1), (2,2), (2,3), (3,2), (1,4), (4,1)
Required probability
$\begin{array}{l} = \frac{2}{6} \times \frac{2}{6} + \frac{1}{6} \times \frac{1}{6} + \frac{2}{6} \times \frac{2}{6} + \frac{2}{6} \times \frac{2}{6} + \frac{1}{6} \times \frac{2}{6} + \frac{2}{6} \times \frac{1}{6} + \frac{1}{6} \times \frac{2}{6} \\ = \frac{18}{36} = \frac{1}{2} \end{array}$

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