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One end of a U-tube of uniform bore (area A) containing mercury is connected to a suction pump. Because of it the level of liquid of density $ρ$ falls in one limb. When the pump is removed, the restoring force in the other limb is:

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$2 xρAg$

$Xρg$

$Aρg$

$xρAg$

answer is A.

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Detailed Solution

Force due to excess pressure =Restoring force
$= (ρgh) A = ρg (2 x) A$

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