One end of a uniform glass capillary tube of radius $r = 0.025 cm$ is immersed vertically in water to a depth h = 1 cm. Contact angle is $0°$, surface tension of water is $7.5\times {10}^{-2}N/m$, density of water is $\rho ={10}^{3}kg/m^3$ and atmospheric pressure is $P_0={10}^{5}N/m^2$

Then find the excess pressure to be applied on the water in the capillary tube so that the water level in the tube becomes same as that in the vessel.(answer in $N/m^2$)