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One end of a uniform wire of length L and of weight W is attached rigidly to a point in the roof and a weight $W_{1}$ is suspended from its lower end. If S is the area of cross – section of the wire, the stress in the wire at a height 3L/4 from its lower end is

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$(W_{1} + W) / S$

$\frac{(W_{1} + \frac{3 W}{4})}{S}$

$(W_{1} + \frac{W}{4}) S$

$W_{1} / S$

answer is C.

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Detailed Solution

Force at a height 3L/4 from its lower end

= Weight suspended + weight of $(\frac{3}{4})$ of the chain

= $W_{1} + (\frac{3 W}{4})$

Stress = $(W_{1} + \frac{3 W}{4}) / S$

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