Q.

One end of an ideal spring of unstretched length I0 = 1 m, is fixed on a frictionless horizontal table. The other end has a small particle of mass 0.1kg attached to it. The particle is projected with a velocity V0 = 9.9 m/s perpendicular to the spring. In the subsequent motion of the particle, maximum elongation of spring is 10cm. The velocity of particle at this instant in m/s is

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a

1

b

90

c

10

d

9

answer is D.

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Detailed Solution

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As the spring force is a central force, The angular momentum of the particle is conserved.

l0=10cm

mV0l=mVl'...(1)

l'=1+0.1=1.1m

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from (1)

we get 9.9×1=V×1.1V=9

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One end of an ideal spring of unstretched length I0 = 1 m, is fixed on a frictionless horizontal table. The other end has a small particle of mass 0.1kg attached to it. The particle is projected with a velocity V0 = 9.9 m/s perpendicular to the spring. In the subsequent motion of the particle, maximum elongation of spring is 10cm. The velocity of particle at this instant in m/s is