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Q.

One end of copper wire of length 2L and cross sectional area A is attached to one end of another copper wire of length L and cross section area 2A. If the free end of the longer wire is at electric potential of 8 volt and free end of shorter wire is at potential of 1volt,what is the potential of junction of two wires.

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a

1.2 V

b

2.1 V

c

2.4 V

d

3.6 V

answer is C.

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Detailed Solution

resistance of the longer wire is R=ρ2LA and  that of the shorter wire is R2=ρL2A R1R2= 41  in series p.d  is directly proportional to resistance so total p.d 8-1= 7V will be distributed 4:1 ratio p.d across first conductior 75x4=5.6 V potential at the junction 8-5.6=2.4V

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