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One end of string which passes through pulley and connected to 10 kg mass at other end is pulled by $100 N$ force. Find out the acceleration of 10 kg mass(in SI units). $(g = 9.8 m / s^{2})$

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Detailed Solution

Since string is pulled by $100 N$ force. So tension in the string is $100 N .$ F.B.D. of 10 kg block
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$100 - 10 g = 10 a$
$100 - 10 \times 9.8 = 10 a$
$a = 0.2 m / s^{2}$

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