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One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively are

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$H_{2} S and {Br}_{2}$

${CO}_{2} and {Cl}_{2}$

$NO and {Cl}_{2}$

${SO}_{2} and {Cl}_{2}$

answer is C.

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Detailed Solution

${Cl}_{2}$ bleaches by oxidation while ${SO}_{2}$ does it by reduction.

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