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One hundred tickets are numbered as $00, 01, 02, ......, 09, 10, 11, ......, 99$ and one ticket is drawn at random from them. If $A$ is the event of getting 9 as the sum of the numbers on the ticket and $B$ is the event of getting 0 as the product of the numbers on the ticket then $P (A \cap B) =$

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$\frac{1}{100}$

$\frac{10}{100}$

$\frac{19}{100}$

$\frac{2}{100}$

answer is B.

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Detailed Solution

A=Sum 9, B=Product 0

$A \cap B =$ Sum of the two numbers is 9 and product 0

$= {09, 90}$

$n (S) = 100$

$n (A \cap B) = 2$

$P (A \cap B) = \frac{2}{100}$

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