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Q.

One lit. of aqueous solution of H2​SO4​ contains 4.9g of the acid. 100ml of this solution is taken in a 1 lit flask and diluted with water upto the mark. The pH of the dilute solution is 

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Detailed Solution

Molarity = 4.998x10001000​

=0.05

100 ml of this solution diluted to 1 litre,

Means N1​V1​=N2​V2​

0.05×100=1000×N2​

N​2=5×10−3

[H2​SO4​]=5×10−3

[H+]=2×5×10−3

pH=−log[H+]

=2

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