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One liter of $N_{2}$ and 2 liter of $O_{2}$ under identical conditions of T and Pare mixed. Find the volume of mixture if the pressure of the mixture is reduced to half of initial value.

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answer is 6.

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Detailed Solution

Here, the pressure of the mixture is reduced to half of initial value. Thus, the value of volume of mixture;

$3 \times P = V \times \frac{P}{2} \Rightarrow V = 6 L$

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