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One litre of a gas weighs 4g at 300 K and 1 atm. If the pressure is reduced to 0.75 atm, the temperature at which one litre at the same gas weighs 2g is

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600 K

900 K

450 K

800 K

answer is C.

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Detailed Solution

$\frac{P_{1} V_{1}}{P_{2} V_{1}} = \frac{W_{1} T_{1}}{W_{2} T_{2}}$

$\frac{1 \times 1}{0.75 \times 1} = \frac{4 \times 300}{2 T_{2}}$

$T_{2} = 450 K$

Hence the required option is C

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