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Q.

One litre of a mixture of CO and CO2 is passed over red hot coke when the volume increased to 1.6 L under the same conditions of temperature and pressure. The volume of CO in the original mixture is

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a

500 ml

b

400 ml

c

800 ml

d

600 ml

answer is A.

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Detailed Solution

Volume of gaseous mixture of CO & CO2 = 1 lit

Volume of the gaseous mixture after passing over red hot coke = 1.6 lit

CO2 reacts with red hot coke but not CO

Let the volume of CO2 in the initial mixture = 'V' lit

then the Volume of CO in the initial mixture = (1 - V) lit

\large \mathop {C{O_2}(g)}\limits_{'V'l}^{1V} + C(s) \to \mathop {2CO(g)}\limits_{'X'l}^{2V} \
\large X = \frac{V \times 2V}{1V} liters

X = '2V' liters

Volume of CO formed due to reduction of CO2 = 2 'V' liters

Volume of CO initially present in the mixture = (1 - V) liters

Total volume of gaseous mixture after the reaction = 2V + (1 - V)

= (1 + V) lit

Given (1 + V) lit = 1.6 lit

V = 0.6 lit

Volume of CO2 in the initial mixture = 600 ml

Volume of CO in the initial mixture = (1000 - 600)

= 400 ml

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