One litre of water contains 10^-7 moles of H⁺ ions. Degree of ionisation of water (in percentage) is

Explanation:

H⁺ ions = 10^-7 moles in 1 litre of water

Molar mass of water (H₂O) = 18 g/mol

Density of water = 1 g/mL

Mass of 1 litre of water = 1000 g

Number of moles of water = 1000 g ÷ 18 g/mol = 55.55 moles

Degree of ionisation (%) = (moles of H⁺ ions ÷ total moles of water) × 100

= (10^-7 ÷ 55.55) × 100

= 1.8 × 10^-9

Final Answer:

The degree of ionisation of water is 1.8 × 10^-9