One molal solution of a carboxylic acid in benzene shows the elevation of boiling point of 1.518 K. The degree of association for dimerization of the acid in benzene is ( $K_{b}$ for benzene is 2.53 K kg ${mole}^{- 1}$ )

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0.6

0.7

0.75

0.8

answer is B.

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Detailed Solution

$∆ T_{b} = K_{b} m = 2.53 \times 1 = 2.53 K, i = \frac{∆ T_{b (observed)}}{∆ T_{b (normal)}} = \frac{1.518}{2.53} = 0.6; i = 1 - α + \frac{α}{n}; i = 1 - 0.6 + \frac{0.6}{2} = 0.7$

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