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One mole of a α emitter of half life equal to 2 days was placed in a sealed tube for 4 days at S.T.P. volume of helium collected is

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22.4 lit

16.8 lit

11.2 lit

5.6 lit

answer is B.

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Detailed Solution

$W = \frac{W_{0}}{2^{n}}; n = \frac{t}{t_{1 / 2}}$ . Initially value of Helium 22.4 lits no of half lives = 2

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