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One mole of a gas is subjected to two processes $A B & B C$ , one after the other as shown in the figure. $B C$ is represented by $P V^{n}$ = constant. We can conclude that (where $T =$ temperature, $W =$ work done by gas, $V =$ volume and $U =$ internal energy).

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$T_{A} = T_{B} = T_{C}$

$V_{A} < V_{B}, P_{B} < P_{C}$

$W_{A B} > W_{B C}$

$T_{A} < T_{B}$

answer is C, D.

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Detailed Solution

$△ V_{A B} = △ V_{B C};$ So area under $A B$ is greater than the area under $B C$ .So $W_{A B} > W_{B C}$

For $A$ to $B$ , $V \propto T$

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