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Q.

One mole of a monoatomic gas is supplied heat such that its molar heat capacity during the process is 2R (R gas constant). If during heating, volume gets doubled, by what factor its temperature change?

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answer is 4.

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Detailed Solution

$Q = n (2 R) (Δ T) = W + U$

$C = C_{V} + \frac{R}{1 - x}$

$\Rightarrow 2 R = \frac{3 R}{2} + \frac{R}{1 - x}$

$\Rightarrow x = - 1$

$P V^{- 1} = c o n s t$

$\Rightarrow T V^{- 2} = c o n s t$

If volume becomes double than, temperature becomes four times.

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