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Q.

One mole of a monoatomic ideal gas undergoes the process A→B in the given P - V diagram. What is the specific heat for this process ?

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a

13R/3

b

2R/3

c

13R/6

d

7R/6

answer is C.

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Detailed Solution

$d Q = d U + d W$

$\begin{array}{l} = C_{v} d T + d w \\ = \frac{3 R}{2} (\frac{30 P_{0} V_{0} - 3 P_{0} V_{0}}{R}) + \frac{1}{2} (3 P_{0} + 6 P_{0}) (5 V_{0} - V_{0}) \\ = \frac{91}{2} P_{0} V_{0} + \frac{30}{2} P_{0} V_{0} \\ C = \frac{d Q}{d T} = \frac{(\frac{117}{2} P_{0} V_{0})}{(\frac{27 P_{0} V_{0}}{R})} = \frac{13}{6} R \end{array}$

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