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Q.

One mole of a non-ideal gas undergoes a change of state (1.0 atm, 3.0 L, 200K) to (4.0 atm, 5.0 L, 250 K) with a change in internal energy (ΔU)=40L−atm. The change in enthalpy of the process in L-atm:

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a

42

b

43

c

57

d

None of these

answer is B.

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Detailed Solution

Change in enthalpy when both pressure and volume are changing,

ΔH=ΔU+Δ(PV)=40+(4×5−1×3)=57.

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