One mole of an ideal diatomic gas (C_v= 5 cal) was transformed from initial 25° C and 1 L to the state when temperature is 100° C and volume 10 L. Then for this process : (R = 2 calories/mol/K)( take calories as unit of energy and kelvin for temperature)

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$Δ G$ of the process given information.

$ΔE = 525$

$ΔH = 525$

$Δ S = 5$ in $\frac{373}{298} + 2$ $n 10$

answer is A, B, D.

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Detailed Solution

$\begin{array}{l} ΔH = 1 \times 7 \times 75 = 525 cal \end{array}$

$ΔE = 1 \times 5 \times 75 = 375 cal$

$Δ S = 1 \times 5$ in $(\frac{373}{298}) + 1 \times 2$ in $l (\frac{10}{1})$

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