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One mole of an ideal gas at an initial temperature of T K does 6R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of the gas will be

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$(T + 4) K$

$(T + 2.4) K$

$(T - 2.4) K$

$(T - 4) K$

answer is D.

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Detailed Solution

$W = \frac{n R}{γ - 1} (T_{1} - T_{2})$

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