One mole of an ideal gas at temperature Tt expands according to the law PV2=a (constant). The work done by the gas till temperature of gas becomes T2 is

pV-2= constantComparing with, pVx= constant, we havex=-2W=nRΔT1-x=(I)(R)T2-T11-(-2)=13RT2-T1

One mole of an ideal gas at temperature Tt expands according to the law PV2=a (constant). The work done by the gas till temperature of gas becomes T2 is

pV-2= constantComparing with, pVx= constant, we havex=-2W=nRΔT1-x=(I)(R)T2-T11-(-2)=13RT2-T1

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One mole of an ideal gas at temperature $T_{t}$ expands according to the law $\frac{P}{V^{2}} = a$ (constant). The work done by the gas till temperature of gas becomes $T_{2}$ is

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$\frac{1}{2} R (T_{3} - T_{1})$

$\frac{1}{3} R (T_{3} - T_{1})$

$\frac{1}{4} R (T_{2} - T_{1})$

$\frac{1}{5} I R (T_{2} - T_{1})$

answer is B.

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Detailed Solution

$p V^{- 2} =$ constant

Comparing with, $p V^{x} =$ constant, we have

$x = - 2$

$W = \frac{n R Δ T}{1 - x} = \frac{(I) (R) (T_{2} - T_{1})}{1 - (- 2)}$

$= \frac{1}{3} R (T_{2} - T_{1})$

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One mole of an ideal gas at temperature Tt expands according to the law PV2=a (constant). The work done by the gas till temperature of gas becomes T2 is

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One mole of an ideal gas at temperature $T_{t}$ expands according to the law $\frac{P}{V^{2}} = a$ (constant). The work done by the gas till temperature of gas becomes $T_{2}$ is