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Q.

One mole of an ideal gas is allowed to expand reversibly and adibatically from a temperature of 27°C . If the work done during the process is 3 kJ , then final temperature of the gas is (Cv = 20 J/K)

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a

195 K

b

150 K

c

100 K

d

255 K

answer is B.

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Detailed Solution

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Given number of moles = 1
Initial temperature = 27°C = 300K
Work done by the system = 3kJ = 3000J
It will be (-) because work is done by the system.
Heat capacity at constant volume (Cv) = 20 J/K
We know that work done
W=nCVT2T1; 3000=1×20T23003000=20T2+600020T2=3000; T2=300020=150K

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