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One mole of an ideal gas undergoes a process whose process equation is given as $P = \frac{P_{0}}{1 + {(\frac{V_{0}}{V})}^{2}}$ Here $P_{0}$ and $V_{0}$ are constants. When the volume of gas is changed from $V_{0}$ to $2 V_{0}$ , temperature of the gas is changed by $[\frac{11 P_{0} V_{0}}{2 N R}]$ Find $N$ (R is universal gas constant)

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Detailed Solution

$T_{2} - T_{1} = \frac{P_{2} V_{2}}{R} - \frac{P_{1} V_{1}}{R}$

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