One mole of an ideal gas whose adiabatic exponent γ=43 undergoes process P=200+1V then change in internal energy of gas when volume changes from 2m3 to 4m3 is (in Joules).

RT=200V+1ΔU=n(Rγ−1)(Tf−Ti)=1R43−1(Tf−Ti)=3R(Tf−Ti)=3×200(Vf−Vi)=1200 J

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One mole of an ideal gas whose adiabatic exponent $γ = \frac{4}{3}$ undergoes process $P = 200 + \frac{1}{V}$ then change in internal energy of gas when volume changes from $2 m^{3}$ to $4 m^{3}$ is (in Joules).

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answer is 1200.

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Detailed Solution

$R T = 200 V + 1$

$Δ U = n (\frac{R}{γ - 1}) (T_{f} - T_{i}) = 1 \frac{R}{\frac{4}{3} - 1} (T_{f} - T_{i}) = 3 R (T_{f} - T_{i}) = 3 \times 200 (V_{f} - V_{i}) = 1200 J$

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