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Q.

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. What will be number of molecules of $H_{2} {SO}_{4}$ present in 100 mL of 0.02 M $H_{2} {SO}_{4}$ a solution?

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a

$12.044 \times 10^{20} molecules$

b

$6.022 \times 10^{23} molecules$

c

$1 \times 10^{23} molecules$

d

$12.044 \times 10^{23} molecules$

answer is A.

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Detailed Solution

$12.044 \times 10^{20} molecules$

$∵ n = C \times V \Rightarrow n = 0.02 \times 0.1 = 0.002 mole of H_{2} {SO}_{4}$

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