One mole of any substance contains 6.022 x 10²³ atoms/molecules. Number of molecules of H₂SO₄  present in 100 mL of 0.02 M H₂SO₄ solution is ______ molecules.

$\mathrm{Molarity} =\frac{ \mathrm{No}.\mathrm{of} \mathrm{moles} \mathrm{of} \mathrm{solute} \times 1000}{ \mathrm{Volume} \mathrm{of} \mathrm{solution} ( \mathrm{in} \mathrm{mL})}$
$\because$ 1 M H₂SO₄ contains 1 mole of H₂SO₄ in 1000 mL of solution
$\because$ 0.02M H₂SO₄ in 100 mL of solution contains $\frac{0.02\times 100}{1000}=2\times {10}^{-3} \mathrm{moles}$
= 2 x 10^-3 x 6.022 x 10²³ = 12.044 x 10²⁰ molecules