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One mole of calcium bicarbonate on strong heating liberates….litres of carbon dioxide at STP

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22.4

44.8

67.2

89.6

answer is B.

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Detailed Solution

$Ca {({HCO}_{3})}_{2} \overset{∆}{\to} {CaCO}_{3} (s) + H_{2} O (g) + {CO}_{2} (g); {CaCO}_{3} (s) \overset{∆}{\to} CaO (s) + {CO}_{2} (g); 44.8 litres of {CO}_{2} is liberated at STP;$

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