One mole of calcium phosphide on reacting with excess of water gives

$\left[{\mathrm{Ca}}_3{\mathrm{P}}_2+6{\mathrm{H}}_2{\mathrm{O}}_3\to \mathrm{Ca}{\left(\mathrm{OH}\right)}_2+2{\mathrm{PH}}_3\right]$

The chemical equation for the reaction of calcium phosphide and excess of water is given below.

$\left[{\mathrm{Ca}}_3{\mathrm{P}}_2+6{\mathrm{H}}_2{\mathrm{O}}_3\to \mathrm{Ca}{\left(\mathrm{OH}\right)}_2+2{\mathrm{PH}}_3\right]$Here , two moles of phosphine $\left({\mathrm{PH}}_3\right)$is formed.