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One mole of chlroine combines with certain weight of a metal giving 111 g of its chloride. The same amount of metal can displace 2 g of hydrogen from an acid. The atomic weight of the metal is

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Detailed Solution

Weight of Chlorine = 71g

Weight of metalchloride = 111g

Weight of metal = 40g

$\large \frac{W_M}{W_{Cl}} = \frac{E_M}{E_{Cl}}$

$\large \frac{40}{71} = \frac{E_M}{35.5}$

40g metal displaces 2 grams of H₂ E_M = 20

$\large \because$ 40g metal displaces 2 g equivalent of H₂ then valency of the metal is 2

$\large \therefore$ AW = EW $\large \times$ 2

AW = 20 $\large \times$ 2 = 40

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