One mole of fluorine is reacted with two moles of hot and concentrated $K O H$ . The Products formed are $K F$ , $H_{2} O$ and $O_{2}$ . The molar ratio of $K F$ , $H_{2} O$ and $O_{2}$ respectively.

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1: 1: 2

2: 1: 0.5

1: 2: 1

2: 1: 2

answer is B.

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Detailed Solution

The balanced equation is:

$F_{2} + 2 K O H \to 2 K F_{} + H {}_{2}O + 1 / 2 O_{2}$

From the balanced equation, we can conclude the ration of $K F$ , $H_{2} O$ and $O_{2}$ as

$K F_{} : H {}_{2}O : O_{2} = 2 : 1 : 1 / 2 = 2 : 1 : 0.5$

Hence the correct option is (B).

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