One mole of fluorine is reacted with two moles of hot and concentrated $KOH$. The  Products formed are $KF$, $H_{2}O$ and $O_2$. The molar ratio of $KF$, $H_{2}O$ and $O_2$ respectively.

The balanced equation is: 

$F_2+2KOH\to 2K{F}_{ }+H{}_{2}O+1/2O_2$

From the balanced equation, we can conclude the ration of $KF$, $H_{2}O$ and $O_2$ as

$K{F}_{ }:H{}_{2}O:O_2=2:1:1/2=2:1:0.5$

Hence the correct option is (B).