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One mole of gas is first cooled from 300 K to 150 K at constant volume and then heated from 150 K to 300 K at constant pressure. The net heat absorbed by the gas is

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150 R

450 R

300 R

Zero

answer is D.

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Detailed Solution

$d Q_{V} = - 1 \times C_{V} \times 150 \to (1)$

$d Q_{P} = 1 \times C_{P} \times 150 \to (2)$

$\begin{array}{l} Q = d Q_{V} + d Q_{P} \\ = 150 (C_{P} - C_{V}) = 150 R \end{array}$

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