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Q.

One mole of He is isothermally expanded from 100 atm to 1 atm. If the work done in a single step is $W_{1} J$ and in 2 steps is $W_{2} J . W_{2} - W_{1}$ is ___________J

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answer is 1222.

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Detailed Solution

$W_{irr} = nRT (1 - \frac{P_{2}}{P_{1}}) = 2469 J . \to W_{1} \begin{array}{l} W_{1} = nRT (1 - \frac{50}{100}) = 1247 J \\ W_{2} = nRT (1 - \frac{1}{50}) = 2444 J \end{array}\} \to W_{2} W_{2} - W_{1} = 3691 - 2469 = 1222 J$

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