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Q.

One mole of ideal gas expands isobarically to double its volume at 27°C. Then the work done by the gas is nearly

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a

2760 cal

b

414 cal

c

1380 cal

d

600 cal

answer is D.

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Detailed Solution

W=PdV=nRdT  ( in isobaric process if volume is doubled temperature also  becomes double so dT=T) =1×2×300 =600cal

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One mole of ideal gas expands isobarically to double its volume at 27°C. Then the work done by the gas is nearly